openFileDialog1.InitialDirectory = Application.StartupPath;

    if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)

    {

        string a = System.IO.File.ReadAllText(openFileDialog1.FileName);

        byte[] b = System.Text.Encoding.Default.GetBytes(a);

        System.IO.MemoryStream c= new System.IO.MemoryStream(b);

        Image img = Image.FromStream(c);

        pic1.Image = img;

    }